Medium
Verify Preorder Sequence in Binary Search Tree — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
bool verifyPreorder(vector<int>& preorder) {
int low = INT_MIN, i = -1;
for (auto& p : preorder) {
if (p < low) {
return false;
}
while (i >= 0 && p > preorder[i]) {
low = preorder[i--];
}
preorder[++i] = p;
}
return true;
}
};
// Time: O(n)
// Space: O(h)
class Solution2 {
public:
bool verifyPreorder(vector<int>& preorder) {
int low = INT_MIN;
stack<int> path;
for (auto& p : preorder) {
if (p < low) {
return false;
}
while (!path.empty() && p > path.top()) {
// Traverse to its right subtree now.
// Use the popped values as a lower bound because
// we shouldn't come across a smaller number anymore.
low = path.top();
path.pop();
}
path.emplace(p);
}
return true;
}
};