Easy
Valid Word Square — C++
Full explanation · Time O(m * n) · Space O(1)
// Time: O(m * n)
// Space: O(1)
class Solution {
public:
bool validWordSquare(vector<string>& words) {
for (int i = 0; i < words.size(); ++i) {
for (int j = 0; j < words[i].size(); ++j) {
if (j >= words.size() || i >= words[j].size() ||
words[j][i] != words[i][j]) {
return false;
}
}
}
return true;
}
};