Easy
Valid Palindrome — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
bool isPalindrome(string s) {
int i = 0, j = s.length() - 1;
while (i < j) {
if (!isalnum(s[i])) {
++i;
} else if (!isalnum(s[j])) {
--j;
} else if (tolower(s[i]) != tolower(s[j])) {
return false;
} else {
++i, --j;
}
}
return true;
}
};
// Time: O(n)
// Space: O(1)
// Iterator solution.
class Solution2 {
public:
bool isPalindrome(string s) {
auto left = s.begin();
auto right = prev(s.end());
while (left < right) {
if (!isalnum(*left)) {
++left;
} else if (!isalnum(*right)) {
--right;
} else if (tolower(*left) != tolower(*right)) {
return false;
} else {
++left, --right;
}
}
return true;
}
};