Hard
Valid Palindrome III — Python
Full explanation · Time O(n^2) · Space O(n)
# Time: O(n^2)
# Space: O(n)
class Solution(object):
def isValidPalindrome(self, s, k):
"""
:type s: str
:type k: int
:rtype: bool
"""
if s == s[::-1]: # optional, to optimize special case
return True
dp = [[1] * len(s) for _ in xrange(2)]
for i in reversed(xrange(len(s))):
for j in xrange(i+1, len(s)):
if s[i] == s[j]:
dp[i%2][j] = 2 + dp[(i+1)%2][j-1] if i+1 <= j-1 else 2
else:
dp[i%2][j] = max(dp[(i+1)%2][j], dp[i%2][j-1])
return len(s) <= k + dp[0][-1]