Easy
Valid Anagram — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
bool isAnagram(string s, string t) {
if (size(s) != size(t)) {
return false;
}
unordered_map<char, int> count;
for (const auto& c: s) {
++count[c];
}
for (const auto& c: t) {
--count[c];
if (count[c] < 0) {
return false;
}
}
return true;
}
};
// Time: O(nlogn)
// Space: O(1)
class Solution2 {
public:
bool isAnagram(string s, string t) {
if (size(s) != size(t)) {
return false;
}
sort(begin(s), end(s));
sort(begin(t), end(t));
return s == t;
}
};