Easy
Univalued Binary Tree — Python
Full explanation · Time O(n) · Space O(h)
# Time: O(n)
# Space: O(h)
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def isUnivalTree(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
s = [root]
while s:
node = s.pop()
if not node:
continue
if node.val != root.val:
return False
s.append(node.left)
s.append(node.right)
return True
# Time: O(n)
# Space: O(h)
class Solution2(object):
def isUnivalTree(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
return (not root.left or (root.left.val == root.val and self.isUnivalTree(root.left))) and \
(not root.right or (root.right.val == root.val and self.isUnivalTree(root.right)))