Medium
Ugly Number II — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(n)
// DP solution. (12ms)
class Solution {
public:
int nthUglyNumber(int n) {
vector<int> uglies(n);
uglies[0] = 1;
int f2 = 2, f3 = 3, f5 = 5;
int idx2 = 0, idx3 = 0, idx5 = 0;
for (int i = 1; i < n; ++i) {
int min_val = min(min(f2, f3), f5);
uglies[i] = min_val;
if (min_val == f2) {
f2 = 2 * uglies[++idx2];
}
if (min_val == f3) {
f3 = 3 * uglies[++idx3];
}
if (min_val == f5) {
f5 = 5 * uglies[++idx5];
}
}
return uglies[n - 1];
}
};
// Time: O(n)
// Space: O(1)
// Heap solution. (148ms)
class Solution2 {
public:
int nthUglyNumber(int n) {
long long ugly_number = 0;
priority_queue<long long , vector<long long>, greater<long long>> heap;
heap.emplace(1);
for (int i = 0; i < n; ++i) {
ugly_number = heap.top();
heap.pop();
if (ugly_number % 2 == 0) {
heap.emplace(ugly_number * 2);
} else if (ugly_number % 3 == 0) {
heap.emplace(ugly_number * 2);
heap.emplace(ugly_number * 3);
} else {
heap.emplace(ugly_number * 2);
heap.emplace(ugly_number * 3);
heap.emplace(ugly_number * 5);
}
}
return ugly_number;
}
};
// BST solution.
class Solution3 {
public:
int nthUglyNumber(int n) {
long long ugly_number = 0;
set<long long> bst;
bst.emplace(1);
for (int i = 0; i < n; ++i) {
ugly_number = *bst.cbegin();
bst.erase(bst.cbegin());
if (ugly_number % 2 == 0) {
bst.emplace(ugly_number * 2);
} else if (ugly_number % 3 == 0) {
bst.emplace(ugly_number * 2);
bst.emplace(ugly_number * 3);
} else {
bst.emplace(ugly_number * 2);
bst.emplace(ugly_number * 3);
bst.emplace(ugly_number * 5);
}
}
return ugly_number;
}
};