Easy
Two Sum IV - Input is a BST — Python
Full explanation · Time O(n) · Space O(h)
# Time: O(n)
# Space: O(h)
class Solution(object):
def findTarget(self, root, k):
"""
:type root: TreeNode
:type k: int
:rtype: bool
"""
class BSTIterator(object):
def __init__(self, root, forward):
self.__node = root
self.__forward = forward
self.__s = []
self.__cur = None
self.next()
def val(self):
return self.__cur
def next(self):
while self.__node or self.__s:
if self.__node:
self.__s.append(self.__node)
self.__node = self.__node.left if self.__forward else self.__node.right
else:
self.__node = self.__s.pop()
self.__cur = self.__node.val
self.__node = self.__node.right if self.__forward else self.__node.left
break
if not root:
return False
left, right = BSTIterator(root, True), BSTIterator(root, False)
while left.val() < right.val():
if left.val() + right.val() == k:
return True
elif left.val() + right.val() < k:
left.next()
else:
right.next()
return False