Hard
Total Characters in String After Transformations II — Python
Full explanation · Time O(n + 26^3 * logt) · Space O(26^2)
# Time: O(n + 26^3 * logt)
# Space: O(26^2)
import itertools
# matrix fast exponentiation
class Solution(object):
def lengthAfterTransformations(self, s, t, nums):
"""
:type s: str
:type t: int
:type nums: List[int]
:rtype: int
"""
MOD = 10**9+7
def matrix_mult(A, B):
ZB = zip(*B)
return [[sum(a*b % MOD for a, b in itertools.izip(row, col)) % MOD for col in ZB] for row in A]
def matrix_expo(A, K):
result = [[int(i == j) for j in xrange(len(A))] for i in xrange(len(A))]
while K:
if K % 2:
result = matrix_mult(result, A)
A = matrix_mult(A, A)
K /= 2
return result
cnt = [0]*26
for x in s:
cnt[ord(x)-ord('a')] += 1
matrix = [[0]*26 for _ in xrange(26)]
for i in xrange(len(nums)):
for j in xrange(1, nums[i]+1):
matrix[i][(i+j)%26] = 1
matrix_pow_t = matrix_expo(matrix, t)
return reduce(lambda accu, x: (accu+x)%MOD, matrix_mult([cnt], matrix_pow_t)[0], 0)