Medium
Total Characters in String After Transformations I — C++
Full explanation · Time precompute: O(t + 26) runtime: O(n) · Space O(t + 26)
// Time: precompute: O(t + 26)
// runtime: O(n)
// Space: O(t + 26)
// precompute, dp
const int MOD = 1e9 + 7;
const int MAX_T = 1e5;
vector<int> init() {
vector<int> DP(MAX_T + 26);
for (int i = 0; i < 26; ++i) {
DP[i] = 1;
}
for (int i = 26; i < size(DP); ++i) {
DP[i] = (DP[i - 26] + DP[(i - 26) + 1]) % MOD;
}
return DP;
}
const auto& DP = init();
class Solution {
public:
int lengthAfterTransformations(string s, int t) {
int result = 0;
for (const auto& x : s) {
result = (result + DP[(x - 'a') + t]) % MOD;
}
return result;
}
};
// Time: O(n + t + 26)
// Space: O(26)
// dp
class Solution2 {
public:
int lengthAfterTransformations(string s, int t) {
static const int MOD = 1e9 + 7;
vector<int> dp(26, 1);
const auto mx = ranges::max(s);
for (int i = 26; i <= (mx - 'a') + t; ++i) {
dp[i % 26] = (dp[(i - 26) % 26] + dp[((i - 26) + 1) % 26]) % MOD;
}
int result = 0;
for (const auto& x : s) {
result = (result + dp[((x - 'a') + t) % 26]) % MOD;
}
return result;
}
};
// Time: O(n + 26^3 * logt)
// Space: O(26^2)
// matrix fast exponentiation
class Solution3 {
public:
int lengthAfterTransformations(string s, int t) {
vector<int> cnt(26);
for (const auto& x : s) {
++cnt[x - 'a'];
}
vector<int> nums(26, 1);
nums.back() = 2;
vector<vector<int>> matrix(26, vector<int>(26));
for (int i = 0; i < size(nums); ++i) {
for (int j = 1; j <= nums[i]; ++j) {
matrix[i][(i + j) % 26] = 1;
}
}
const auto& matrix_pow_t = matrixExpo(matrix, t);
const auto& result = matrixMult(vector<vector<int>>{{cnt}}, matrix_pow_t);
return accumulate(cbegin(result[0]), cend(result[0]), 0, [](const auto& accu, const auto& x) {
return (accu + x) % MOD;
});
}
private:
vector<vector<int>> matrixExpo(const vector<vector<int>>& A, int64_t pow) {
vector<vector<int>> result(A.size(), vector<int>(A.size()));
vector<vector<int>> A_exp(A);
for (int i = 0; i < A.size(); ++i) {
result[i][i] = 1;
}
while (pow) {
if (pow % 2 == 1) {
result = matrixMult(result, A_exp);
}
A_exp = matrixMult(A_exp, A_exp);
pow /= 2;
}
return result;
}
vector<vector<int>> matrixMult(const vector<vector<int>>& A, const vector<vector<int>>& B) {
vector<vector<int>> result(A.size(), vector<int>(B[0].size()));
for (int i = 0; i < A.size(); ++i) {
for (int j = 0; j < B[0].size(); ++j) {
int64_t entry = 0;
for (int k = 0; k < B.size(); ++k) {
entry = (static_cast<int64_t>(A[i][k]) * B[k][j] % MOD + entry) % MOD;
}
result[i][j] = static_cast<int>(entry);
}
}
return result;
}
static const int MOD = 1e9 + 7;
};
// Time: O(n + t * 26)
// Space: O(26)
// dp
class Solution4 {
public:
int lengthAfterTransformations(string s, int t) {
vector<int> cnt(26);
for (const auto& x : s) {
++cnt[x - 'a'];
}
for (int _ = 0; _ < t; ++_) {
vector<int> new_cnt(26);
for (int i = 0; i < 26; ++i) {
new_cnt[(i + 1) % 26] = (new_cnt[(i + 1) % 26] + cnt[i]) % MOD;
if (i == 25) {
new_cnt[(i + 2) % 26] = (new_cnt[(i + 2) % 26] + cnt[i]) % MOD;
}
}
cnt = move(new_cnt);
}
return accumulate(cbegin(cnt), cend(cnt), 0, [](const auto& accu, const auto& x) {
return (accu + x) % MOD;
});
}
};