Medium
Top K Frequent Elements — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// Bucket Sort Solution
class Solution {
public:
vector<int> topKFrequent(vector<int>& nums, int k) {
unordered_map<int, int> counts;
for (const auto& i : nums) {
++counts[i];
}
vector<vector<int>> buckets(nums.size() + 1);
for (const auto& kvp : counts) {
buckets[kvp.second].emplace_back(kvp.first);
}
vector<int> result;
for (int i = buckets.size() - 1; i >= 0; --i) {
for (int j = 0; j < buckets[i].size(); ++j){
result.emplace_back(buckets[i][j]);
if (result.size() == k) {
return result;
}
}
}
return result;
}
};
// Time: O(n) ~ O(n^2), O(n) on average.
// Space: O(n)
// Quick Select Solution
class Solution2 {
public:
vector<int> topKFrequent(vector<int>& nums, int k) {
unordered_map<int, int> counts;
for (const auto& i : nums) {
++counts[i];
}
vector<pair<int, int>> p;
for (const auto& kvp : counts) {
p.emplace_back(-kvp.second, kvp.first);
}
nth_element(p.begin(), p.begin() + k - 1, p.end());
vector<int> result;
for (int i = 0; i < k; ++i) {
result.emplace_back(p[i].second);
}
return result;
}
};
// Time: O(nlogk)
// Space: O(n)
// Heap solution.
class Solution3 {
public:
vector<int> topKFrequent(vector<int>& nums, int k) {
unordered_map<int, int> counts;
for (const auto& i : nums) {
++counts[i];
}
priority_queue<pair<int, int>> heap;
for (const auto& kvp : counts) {
heap.emplace(-kvp.second, kvp.first);
if (heap.size() == k + 1) {
heap.pop();
}
}
vector<int> result;
while (!heap.empty()) {
result.emplace_back(heap.top().second);
heap.pop();
}
reverse(result.begin(), result.end());
return result;
}
};