Hard
Time Taken to Cross the Door — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// queue, simulation
class Solution {
public:
vector<int> timeTaken(vector<int>& arrival, vector<int>& state) {
enum {UNKNOWN = -1, ENTERING, EXITING};
vector<int> result(size(arrival));
int curr = numeric_limits<int>::min(), direction = UNKNOWN;
vector<queue<int>> q(2);
const auto& go_until = [&](int t) {
while (curr <= t && any_of(cbegin(q), cend(q), [](const auto& x) { return !empty(x); })) {
if (empty(q[direction])) {
direction ^= 1;
}
result[q[direction].front()] = curr++;
q[direction].pop();
}
};
for (int i = 0; i < size(arrival); ++i) {
go_until(arrival[i] - 1);
q[state[i]].emplace(i);
if (!(arrival[i] <= curr)) {
curr = arrival[i], direction = EXITING;
}
}
go_until(numeric_limits<int>::max());
return result;
}
};