Easy
Time Needed to Buy Tickets — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int timeRequiredToBuy(vector<int>& tickets, int k) {
int result = 0;
for (int i = 0; i < size(tickets); ++i) {
result += min(tickets[i], i <= k ? tickets[k]: tickets[k] - 1);
}
return result;
}
};