Medium
Take K of Each Character From Left and Right — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# sliding window, two pointers
class Solution(object):
def takeCharacters(self, s, k):
"""
:type s: str
:type k: int
:rtype: int
"""
cnt = [0]*3
for c in s:
cnt[ord(c)-ord('a')] += 1
if min(cnt) < k:
return -1
result = left = 0
for right in xrange(len(s)):
cnt[ord(s[right])-ord('a')] -= 1
while cnt[ord(s[right])-ord('a')] < k:
cnt[ord(s[left])-ord('a')] += 1
left += 1
result = max(result, right-left+1)
return len(s)-result