Easy
Sum of Square Numbers — Python
Full explanation · Time O(sqrt(c) * logc) · Space O(1)
# Time: O(sqrt(c) * logc)
# Space: O(1)
import math
class Solution(object):
def judgeSquareSum(self, c):
"""
:type c: int
:rtype: bool
"""
for a in xrange(int(math.sqrt(c))+1):
b = int(math.sqrt(c-a**2))
if a**2 + b**2 == c:
return True
return False