Medium
Sum of Primes Between Number and Its Reverse — C++
Full explanation · Time precompute: O(r) runtime: O(1) · Space O(r)
// Time: precompute: O(r)
// runtime: O(1)
// Space: O(r)
// number theory, prefix sum
vector<int> linear_sieve_of_eratosthenes(int n) { // Time: O(n), Space: O(n)
vector<int> spf(n + 1, -1);
vector<int> primes;
for (int i = 2; i <= n; ++i) {
if (spf[i] == -1) {
spf[i] = i;
primes.emplace_back(i);
}
for (const auto& p : primes) {
if (i * p > n || p > spf[i]) {
break;
}
spf[i * p] = p;
}
}
return spf;
}
const auto& precompute = [](int n) {
const auto& spf = linear_sieve_of_eratosthenes(n);
vector<int> prefix(size(spf) + 1);
for (int i = 0; i + 1 < size(prefix); ++i) {
prefix[i + 1] = prefix[i] + (spf[i] == i ? i : 0);
}
return prefix;
};
const int MAX_N = 1000;
const auto& PREFIX = precompute(MAX_N);
class Solution {
public:
int sumOfPrimesInRange(int n) {
const auto& reverse = [](int n) {
int result = 0;
for (; n; n /= 10) {
result = result * 10 + n % 10;
}
return result;
};
const auto& [left, right] = minmax(n, reverse(n));
return PREFIX[right + 1] - PREFIX[left];
}
};