Easy
Sum of Left Leaves — C++
Full explanation · Time O(n) · Space O(h)
// Time: O(n)
// Space: O(h)
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int sumOfLeftLeaves(TreeNode* root) {
return sumOfLeftLeavesHelper(root, false);
}
private:
int sumOfLeftLeavesHelper(TreeNode* root, bool is_left) {
if (!root) {
return 0;
}
if (!root->left && !root->right) {
return is_left ? root->val : 0;
}
return sumOfLeftLeavesHelper(root->left, true) +
sumOfLeftLeavesHelper(root->right, false);
}
};