Medium
Sum of Largest Prime Substrings — Python
Full explanation · Time O(n^2 * sqrt(r)) · Space O(n^2)
# Time: O(n^2 * sqrt(r))
# Space: O(n^2)
import random
# number theory, quick select
class Solution(object):
def sumOfLargestPrimes(self, s):
"""
:type s: str
:rtype: int
"""
COUNT = 3
def nth_element(nums, n, left=0, compare=lambda a, b: a < b):
def tri_partition(nums, left, right, target, compare):
mid = left
while mid <= right:
if nums[mid] == target:
mid += 1
elif compare(nums[mid], target):
nums[left], nums[mid] = nums[mid], nums[left]
left += 1
mid += 1
else:
nums[mid], nums[right] = nums[right], nums[mid]
right -= 1
return left, right
right = len(nums)-1
while left <= right:
pivot_idx = random.randint(left, right)
pivot_left, pivot_right = tri_partition(nums, left, right, nums[pivot_idx], compare)
if pivot_left <= n <= pivot_right:
return
elif pivot_left > n:
right = pivot_left-1
else: # pivot_right < n.
left = pivot_right+1
def is_prime(n):
if n == 1:
return False
if n in (2, 3):
return True
if n%2 == 0 or n%3 == 0:
return False
for i in xrange(5, n, 6):
if i*i > n:
break
if n%i == 0 or n%(i+2) == 0:
return False
return True
primes_set = set()
for i in xrange(len(s)):
curr = 0
for j in xrange(i, len(s)):
curr = curr*10+int(s[j])
if is_prime(curr):
primes_set.add(curr)
primes = list(primes_set)
d = min(len(primes), COUNT)
nth_element(primes, d, compare=lambda a, b: a > b)
return sum(primes[i] for i in xrange(d))