Hard
Sum of K-Digit Numbers in a Range — Python
Full explanation · Time O(logr) · Space O(1)
# Time: O(logr)
# Space: O(1)
# math
class Solution(object):
def sumOfNumbers(self, l, r, k):
"""
:type l: int
:type r: int
:type k: int
:rtype: int
"""
def invmod(x, MOD):
return pow(x, MOD-2, MOD)
MOD = 10**9+7
return (((((r+l)*(r-l+1)//2)*pow(r-l+1, k-1, MOD))%MOD)*((((pow(10, k, MOD)-1)%MOD)*invmod(10-1, MOD))%MOD))%MOD