Medium
Subsequence of Size K With the Largest Even Sum — Python
Full explanation · Time O(n) on average · Space O(1)
# Time: O(n) on average
# Space: O(1)
import random
# quick select solution
class Solution(object):
def largestEvenSum(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
def nth_element(nums, n, compare=lambda a, b: a < b):
def tri_partition(nums, left, right, target, compare):
mid = left
while mid <= right:
if nums[mid] == target:
mid += 1
elif compare(nums[mid], target):
nums[left], nums[mid] = nums[mid], nums[left]
left += 1
mid += 1
else:
nums[mid], nums[right] = nums[right], nums[mid]
right -= 1
return left, right
left, right = 0, len(nums)-1
while left <= right:
pivot_idx = random.randint(left, right)
pivot_left, pivot_right = tri_partition(nums, left, right, nums[pivot_idx], compare)
if pivot_left <= n <= pivot_right:
return
elif pivot_left > n:
right = pivot_left-1
else: # pivot_right < n.
left = pivot_right+1
nth_element(nums, k-1, compare=lambda a, b: a > b)
total = sum(nums[i] for i in xrange(k))
if total%2 == 0:
return total
min_k = [float("inf")]*2
for i in xrange(k):
min_k[nums[i]%2] = min(min_k[nums[i]%2], nums[i])
result = -1
for i in xrange(k, len(nums)):
result = max(result, total-min_k[not (nums[i]%2)]+nums[i])
return result