Hard
Steps to Make Array Non-decreasing — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// mono stack, dp
class Solution {
public:
int totalSteps(vector<int>& nums) {
vector<int> dp(size(nums)); // dp[i]: number of rounds for nums[i] to remove all the covered elements
vector<int> stk;
for (int i = size(nums) - 1; i >= 0; --i) {
while (!empty(stk) && nums[stk.back()] < nums[i]) {
dp[i] = max(dp[i] + 1, dp[stk.back()]); stk.pop_back();
}
stk.emplace_back(i);
}
return *max_element(cbegin(dp), cend(dp));
}
};
// Time: O(n)
// Space: O(n)
// mono stack, dp
class Solution2 {
public:
int totalSteps(vector<int>& nums) {
vector<int> dp(size(nums)); // dp[i]: number of rounds for nums[i] to be removed
vector<int> stk;
for (int i = 0; i < size(nums); ++i) {
int curr = 0;
while (!empty(stk) && nums[stk.back()] <= nums[i]) {
curr = max(curr, dp[stk.back()]); stk.pop_back();
}
if (!empty(stk)) {
dp[i] = curr + 1;
}
stk.emplace_back(i);
}
return *max_element(cbegin(dp), cend(dp));
}
};