Easy
Split a String in Balanced Strings — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int balancedStringSplit(string s) {
int result = 0, count = 0;
for (const auto& c : s) {
count += (c == 'L') ? 1 : -1;
if (count == 0) {
++result;
}
}
return result;
}
};