Easy
Special Array With X Elements Greater Than or Equal X — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# counting sort solution
class Solution(object):
def specialArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MAX_NUM = 1000
count = [0]*(MAX_NUM+1)
for num in nums:
count[num] += 1
n = len(nums)
for i in xrange(len(count)):
if i == n:
return i
n -= count[i]
return -1
# Time: O(n)
# Space: O(1)
# counting sort + binary search solution
class Solution2(object):
def specialArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MAX_NUM = 1000
def inplace_counting_sort(nums, reverse=False): # Time: O(n)
count = [0]*(MAX_NUM+1)
for num in nums:
count[num] += 1
for i in xrange(1, len(count)):
count[i] += count[i-1]
for i in reversed(xrange(len(nums))): # inplace but unstable sort
while nums[i] >= 0:
count[nums[i]] -= 1
j = count[nums[i]]
nums[i], nums[j] = nums[j], ~nums[i]
for i in xrange(len(nums)):
nums[i] = ~nums[i] # restore values
if reverse: # unstable sort
nums.reverse()
inplace_counting_sort(nums, reverse=True)
left, right = 0, len(nums)-1
while left <= right: # Time: O(logn)
mid = left + (right-left)//2
if nums[mid] <= mid:
right = mid-1
else:
left = mid+1
return -1 if left < len(nums) and nums[left] == left else left
# Time: O(n)
# Space: O(n)
# counting sort + binary search solution
class Solution3(object):
def specialArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MAX_NUM = 1000
def counting_sort(nums, reverse=False): # Time: O(n), Space: O(n)
count = [0]*(MAX_NUM+1)
for num in nums:
count[num] += 1
for i in xrange(1, len(count)):
count[i] += count[i-1]
result = [0]*len(nums)
if not reverse:
for num in reversed(nums): # stable sort
count[num] -= 1
result[count[num]] = num
else:
for num in nums: # stable sort
count[num] -= 1
result[count[num]] = num
result.reverse()
return result
nums = counting_sort(nums, reverse=True) # extra O(n) space for stable sort
left, right = 0, len(nums)-1
while left <= right: # Time: O(logn)
mid = left + (right-left)//2
if nums[mid] <= mid:
right = mid-1
else:
left = mid+1
return -1 if left < len(nums) and nums[left] == left else left
# Time: O(nlogn)
# Space: O(1)
# sort solution
class Solution4(object):
def specialArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
nums.sort(reverse=True) # Time: O(nlogn)
for i in xrange(len(nums)): # Time: O(n)
if nums[i] <= i:
break
else:
i += 1
return -1 if i < len(nums) and nums[i] == i else i