Easy
Sort Array By Parity — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class Solution(object):
def sortArrayByParity(self, A):
"""
:type A: List[int]
:rtype: List[int]
"""
i = 0
for j in xrange(len(A)):
if A[j] % 2 == 0:
A[i], A[j] = A[j], A[i]
i += 1
return A