Medium
Smallest Value After Replacing With Sum of Prime Factors — Python
Full explanation · Time O(s * logn) · Space O(maxn^0.5)
# Time: O(s * logn), s is the times of simulation
# Space: O(max_n^0.5)
# number theory, simulation
def linear_sieve_of_eratosthenes(n): # Time: O(n), Space: O(n)
primes = []
spf = [-1]*(n+1) # the smallest prime factor
for i in xrange(2, n+1):
if spf[i] == -1:
spf[i] = i
primes.append(i)
for p in primes:
if i*p > n or p > spf[i]:
break
spf[i*p] = p
return primes
MAX_N = 10**5
PRIMES = linear_sieve_of_eratosthenes(int(MAX_N**0.5))
class Solution(object):
def smallestValue(self, n):
"""
:type n: int
:rtype: int
"""
while True:
curr, new_n = n, 0
for p in PRIMES:
if p**2 > curr:
break
while curr%p == 0:
curr //= p
new_n += p
if curr > 1: # curr is a prime
new_n += curr
if new_n == n:
break
n = new_n
return n