Hard
Smallest Rotation with Highest Score — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(n)
class Solution(object):
def bestRotation(self, A):
"""
:type A: List[int]
:rtype: int
"""
N = len(A)
change = [1] * N
for i in xrange(N):
change[(i-A[i]+1)%N] -= 1
for i in xrange(1, N):
change[i] += change[i-1]
return change.index(max(change))