Easy
Smallest Pair With Different Frequencies — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// freq table
class Solution {
public:
vector<int> minDistinctFreqPair(vector<int>& nums) {
static const int INF = numeric_limits<int>::max();
unordered_map<int, int> cnt;
for (const auto& x : nums) {
++cnt[x];
}
const auto& x = ranges::min(nums);
int mn = INF;
for (const auto& y : nums) {
if (cnt[y] != cnt[x]) {
mn = min(mn, y);
}
}
return mn != INF ? vector<int>{x, mn} : vector<int>{-1, -1};
}
};