Medium
Simplified Fractions — C++
Full explanation · Time O(n^2 * logn) · Space O(n^2)
// Time: O(n^2 * logn)
// Space: O(n^2)
class Solution {
public:
vector<string> simplifiedFractions(int n) {
unordered_set<pair<int, int>, PairHash<int>> lookup;
for (int b = 1; b <= n; ++b) {
for (int a = 1; a < b; ++a) {
const auto& g = gcd(a, b);
lookup.emplace(a / g, b / g);
}
}
vector<string> result;
transform(cbegin(lookup), cend(lookup), back_inserter(result),
[](const auto& kvp) {
return to_string(kvp.first) + "/" + to_string(kvp.second);
});
return result;
}
private:
template <typename T>
struct PairHash {
size_t operator()(const pair<T, T>& p) const {
size_t seed = 0;
seed ^= std::hash<T>{}(p.first) + 0x9e3779b9 + (seed<<6) + (seed>>2);
seed ^= std::hash<T>{}(p.second) + 0x9e3779b9 + (seed<<6) + (seed>>2);
return seed;
}
};
};