Hard

Shortest Common SupersequenceC++

Full explanation · Time O(m * n) · Space O(m * n)

// Time:  O(m * n)
// Space: O(m * n)

class Solution {
public:
    string shortestCommonSupersequence(string str1, string str2) {
        vector<vector<int>> dp(2, vector<int>(str2.size() + 1));
        vector<vector<tuple<int, int, char>>> bt(str1.size() + 1,
                                                 vector<tuple<int, int, char>>(str2.size() + 1));
        for (int i = 0; i < str1.length(); ++i) {
            bt[i + 1][0] = {i, 0, str1[i]};
        }
        for (int j = 0; j < str2.length(); ++j) {
            bt[0][j + 1] = {0, j, str2[j]};
        }
        for (int i = 0; i < str1.length(); ++i) {
            for (int j = 0; j < str2.length(); ++j) {
                if (dp[i % 2][j + 1] > dp[(i + 1) % 2][j]) {
                    dp[(i + 1) % 2][j + 1] = dp[i % 2][j + 1];
                    bt[i + 1][j + 1] = {i, j + 1, str1[i]};
                } else {
                    dp[(i + 1) % 2][j + 1] = dp[(i + 1) % 2][j];
                    bt[i + 1][j + 1] = {i + 1, j, str2[j]};
                }
                if (str1[i] != str2[j]) {
                    continue;
                }
                if (dp[i % 2][j] + 1 > dp[(i + 1) % 2][j + 1]) {
                    dp[(i + 1) % 2][j + 1] = dp[i % 2][j] + 1;
                    bt[i + 1][j + 1] = {i, j, str1[i]};
                }
            }
        }
        
        int i = str1.length(), j = str2.length();
        char c = 0;
        string result;
        while (i != 0 || j != 0) {
            tie(i, j, c) = bt[i][j];
            result.push_back(c);
        }
        reverse(result.begin(), result.end());
        return result;
    }
};