Medium
Search in Rotated Sorted Array II — Python
Full explanation · Time O(logn) ~ O(n) · Space O(1)
# Time: O(logn) ~ O(n)
# Space: O(1)
class Solution(object):
def search(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: int
"""
left, right = 0, len(nums) - 1
while left <= right:
mid = left + (right - left) / 2
if nums[mid] == target:
return True
elif nums[mid] == nums[left]:
left += 1
elif (nums[mid] > nums[left] and nums[left] <= target < nums[mid]) or \
(nums[mid] < nums[left] and not (nums[mid] < target <= nums[right])):
right = mid - 1
else:
left = mid + 1
return False