Hard
Russian Doll Envelopes — Python
Full explanation · Time O(nlogn) · Space O(1)
# Time: O(nlogn + nlogk) = O(nlogn), k is the length of the result.
# Space: O(1)
class Solution(object):
def maxEnvelopes(self, envelopes):
"""
:type envelopes: List[List[int]]
:rtype: int
"""
def insert(target):
left, right = 0, len(result) - 1
while left <= right:
mid = left + (right - left) / 2
if result[mid] >= target:
right = mid - 1
else:
left = mid + 1
if left == len(result):
result.append(target)
else:
result[left] = target
result = []
envelopes.sort(lambda x, y: y[1] - x[1] if x[0] == y[0] else \
x[0] - y[0])
for envelope in envelopes:
insert(envelope[1])
return len(result)