Medium
Redundant Connection — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(nlog*n) ~= O(n), n is the length of the positions
# Space: O(n)
class UnionFind(object):
def __init__(self, n):
self.set = range(n)
def find_set(self, x):
if self.set[x] != x:
self.set[x] = self.find_set(self.set[x]) # path compression.
return self.set[x]
def union_set(self, x, y):
x_root, y_root = map(self.find_set, (x, y))
if x_root == y_root:
return False
self.set[min(x_root, y_root)] = max(x_root, y_root)
return True
class Solution(object):
def findRedundantConnection(self, edges):
"""
:type edges: List[List[int]]
:rtype: List[int]
"""
union_find = UnionFind(len(edges)+1)
for edge in edges:
if not union_find.union_set(*edge):
return edge
return []