Hard
Rearrange String k Distance Apart — C++
Full explanation · Time O(n) · Space O(c)
// Time: O(n)
// Space: O(c)
class Solution {
public:
string rearrangeString(string s, int k) {
if (!k) {
return s;
}
unordered_map<char, int> cnts;
for (const auto& c : s) {
++cnts[c];
}
const int bucket_cnt = max_element(cbegin(cnts), cend(cnts), [](const auto& a, const auto& b) {
return a.second < b.second;
})->second;
if (!((bucket_cnt - 1) * k + count_if(cbegin(cnts), cend(cnts), [&](const auto& x) { return x.second == bucket_cnt; }) <= size(s))) {
return "";
}
vector<char> partial_sorted_cnts;
for (const auto& [c, v] : cnts) {
if (v == bucket_cnt) {
partial_sorted_cnts.emplace_back(c);
}
}
for (const auto& [c, v] : cnts) {
if (v != bucket_cnt) {
partial_sorted_cnts.emplace_back(c);
}
}
string result(size(s), 0);
int i = (size(s) - 1) % k;
for (const auto& c : partial_sorted_cnts) {
for (int _ = 0; _ < cnts[c]; ++_) {
result[i] = c;
i += k;
if (i >= size(result)) {
i = (i - 1) % k;
}
}
}
return result;
}
};
// Time: O(n)
// Space: O(c)
// reference: https://codeforces.com/blog/entry/110184 1774B - Coloring
class Solution2 {
public:
string rearrangeString(string s, int k) {
if (!k) {
return s;
}
unordered_map<char, int> cnts;
for (const auto& c : s) {
++cnts[c];
}
const int bucket_cnt = (size(s) + k - 1) / k;
const int mx = max_element(cbegin(cnts), cend(cnts), [](const auto& a, const auto& b) {
return a.second < b.second;
})->second;
if (!(mx <= bucket_cnt && count_if(cbegin(cnts), cend(cnts), [&](const auto& x) { return x.second == bucket_cnt; }) <= (size(s) - 1) % k + 1)) {
return "";
}
vector<char> partial_sorted_cnts;
for (const auto& [c, v] : cnts) {
if (v == bucket_cnt) {
partial_sorted_cnts.emplace_back(c);
}
}
for (const auto& [c, v] : cnts) {
if (v <= bucket_cnt - 2) {
partial_sorted_cnts.emplace_back(c);
}
}
for (const auto& [c, v] : cnts) {
if (v == bucket_cnt - 1) {
partial_sorted_cnts.emplace_back(c);
}
}
string result(size(s), 0);
int i = 0;
for (const auto& c : partial_sorted_cnts) {
for (int _ = 0; _ < cnts[c]; ++_) {
result[i] = c;
i += k;
if (i >= size(result)) {
i = i % k + 1;
}
}
}
return result;
}
};
// Time: O(n)
// Space: O(n)
class Solution3 {
public:
string rearrangeString(string s, int k) {
unordered_map<char, int> cnts;
for (const auto& c : s) {
++cnts[c];
}
const int bucket_cnt = max_element(cbegin(cnts), cend(cnts), [](const auto& a, const auto& b) {
return a.second < b.second;
})->second;
vector<char> partial_sorted_cnts;
for (const auto& [c, v] : cnts) {
if (v == bucket_cnt) {
partial_sorted_cnts.emplace_back(c);
}
}
for (const auto& [c, v] : cnts) {
if (v == bucket_cnt - 1) {
partial_sorted_cnts.emplace_back(c);
}
}
for (const auto& [c, v] : cnts) {
if (v <= bucket_cnt - 2) {
partial_sorted_cnts.emplace_back(c);
}
}
vector<string> buckets(bucket_cnt);
int i = 0;
for (const auto& c : partial_sorted_cnts) {
for (int _ = 0; _ < cnts[c]; ++_) {
buckets[i].push_back(c);
i = (i + 1) % max(cnts[c], bucket_cnt - 1);
}
}
string result;
for (int i = 0; i < size(buckets) - 1; ++i) {
if (size(buckets[i]) < k) {
return "";
} else {
result += buckets[i];
}
}
result += buckets[bucket_cnt - 1];
return result;
}
};
// Time: O(nlogc), c is the count of unique characters.
// Space: O(c)
class Solution4 {
public:
string rearrangeString(string s, int k) {
if (k == 0) {
return s;
}
unordered_map<char, int> cnts;
for (const auto& c : s) {
++cnts[c];
}
priority_queue<pair<int, char>> heap;
for (const auto& kvp : cnts) {
heap.emplace(kvp.second, kvp.first);
}
string result;
while (!heap.empty()) {
vector<pair<int, char>> used_cnt_chars;
int cnt = min(k, static_cast<int>(s.length() - result.length()));
for (int i = 0; i < cnt; ++i) {
if (heap.empty()) {
return "";
}
auto cnt_char = heap.top();
heap.pop();
result.push_back(cnt_char.second);
if (--cnt_char.first > 0) {
used_cnt_chars.emplace_back(move(cnt_char));
}
}
for (auto& cnt_char: used_cnt_chars) {
heap.emplace(move(cnt_char));
}
}
return result;
}
};