Medium
Rearrange K Substrings to Form Target String — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// freq table
class Solution {
public:
bool isPossibleToRearrange(string s, string t, int k) {
unordered_map<string, int> cnt;
for (int i = 0, l = size(s) / k; i < size(s); i += l) {
++cnt[s.substr(i, l)];
--cnt[t.substr(i, l)];
}
return all_of(cbegin(cnt), cend(cnt), [](const auto& x) {
return x.second == 0;
});
}
};