Medium

Product of Array Except SelfC++

Full explanation · Time O(n) · Space O(1)

// Time:  O(n)
// Space: O(1)

class Solution {
public:
    vector<int> productExceptSelf(vector<int>& nums) {
        if (nums.empty()) {
            return {};
        }

        vector<int> left_product(nums.size());

        left_product[0] = 1;
        for (int i = 1; i < nums.size(); ++i) {
            left_product[i] = left_product[i - 1] * nums[i - 1];
        }

        int right_product = 1;
        for (int i = static_cast<int>(nums.size()) - 2; i >= 0; --i) {
            right_product *= nums[i + 1];
            left_product[i] = left_product[i] * right_product;
        }

        return left_product;
    }
};