Hard
Power of Heroes — Python
Full explanation · Time O(nlogn) · Space O(1)
# Time: O(nlogn)
# Space: O(1)
# sort, combinatorics, dp
class Solution(object):
def sumOfPower(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MOD = 10**9+7
nums.sort()
result = dp = 0
for x in nums:
result = (result+(x**2)*(dp+x))%MOD
dp = (dp+(dp+x))%MOD
return result