Easy
Positions of Large Groups — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
vector<vector<int>> largeGroupPositions(string S) {
vector<vector<int>> result;
for (int i = 0, j = 0; j < S.length(); ++j) {
if (j == S.length() - 1 || S[j] != S[j + 1]) {
if (j - i + 1 >= 3) {
result.emplace_back(vector<int>{i, j});
}
i = j + 1;
}
}
return result;
}
};