Easy
Path Crossing — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
class Solution {
public:
bool isPathCrossing(string path) {
unordered_set<pair<int, int>, PairHash<int>> lookup = {{0, 0}};
int x = 0, y = 0;
for (const auto& c : path) {
switch(c) {
case 'E':
++x;
break;
case 'W':
--x;
break;
case 'N':
++y;
break;
case 'S':
--y;
break;
}
if (!lookup.emplace(x, y).second) {
return true;
}
}
return false;
}
private:
template <typename T>
struct PairHash {
size_t operator()(const pair<T, T>& p) const {
size_t seed = 0;
seed ^= std::hash<T>{}(p.first) + 0x9e3779b9 + (seed<<6) + (seed>>2);
seed ^= std::hash<T>{}(p.second) + 0x9e3779b9 + (seed<<6) + (seed>>2);
return seed;
}
};
};