Easy
Pascal's Triangle — C++
Full explanation · Time O(n^2) · Space O(1)
// Time: O(n^2)
// Space: O(1)
class Solution {
public:
vector<vector<int>> generate(int numRows) {
vector<vector<int>> result;
for (int i = 0; i < numRows; ++i) {
result.push_back({});
for (int j = 0; j <= i; ++j) {
if (j == 0 || j == i) {
result[i].emplace_back(1);
} else {
result[i].emplace_back(result[i - 1][j - 1] +
result[i - 1][j]);
}
}
}
return result;
}
};