Medium
Partition Array Such That Maximum Difference Is K — C++
Full explanation · Time O(nlogn) · Space O(1)
// Time: O(nlogn)
// Space: O(1)
// sort, greedy
class Solution {
public:
int partitionArray(vector<int>& nums, int k) {
sort(begin(nums), end(nums));
int result = 1;
for (int i = 0, prev = 0; i < size(nums); ++i) {
if (nums[i] - nums[prev] <= k) {
continue;
}
prev = i;
++result;
}
return result;
}
};