Partition Array Into Two Arrays to Minimize Sum Difference — C++

// Time:  O(n * 2^n)
// Space: O(2^n)

class Solution {
public:
    int minimumDifference(vector<int>& nums) {
        vector<int> left, right; 
        for (int i = 0; i < size(nums); ++i) {
            if (i < size(nums) / 2) {
                left.emplace_back(nums[i]); 
            } else {
                right.emplace_back(nums[i]); 
            }
        }
        const auto& total1 = accumulate(cbegin(left), cend(left), 0);
        const auto& total2 = accumulate(cbegin(right), cend(right), 0);
        const int bound = (1 << size(left));
        unordered_map<int, vector<int>> sums;
        for (int mask = 0; mask < bound; ++mask) {
            int total = 0, bit = 1;
            for (const auto& x : left) {
                if (mask & bit) {
                    total += x; 
                }
                bit <<= 1;
            }
            sums[__builtin_popcount(mask)].emplace_back(2 * total - total1); 
        }
        for (auto& [_, v] : sums) {
            sort(begin(v), end(v));
        }
        int result = numeric_limits<int>::max();
        for (int mask = 0; mask < bound; ++mask) {
            int total = 0, bit = 1;
            for (const auto& x : right) {
                if (mask & bit) {
                    total += x; 
                }
                bit <<= 1;
            }
            const int k = size(right) - __builtin_popcount(mask);
            const int diff = 2 * total - total2; 
            const auto cit = lower_bound(cbegin(sums[k]), cend(sums[k]), -diff); 
            if (cit != cend(sums[k])) {
                result = min(result, abs(*cit + diff)); 
            }
            if (cit != cbegin(sums[k])) {
                result = min(result, abs(*prev(cit) + diff));    
            }
        }
        return result; 
    }
};