Easy
Partition Array Into Three Parts With Equal Sum — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class Solution(object):
def canThreePartsEqualSum(self, A):
"""
:type A: List[int]
:rtype: bool
"""
total = sum(A)
if total % 3 != 0:
return False
parts, curr = 0, 0
for x in A:
curr += x
if curr == total//3:
parts += 1
curr = 0
return parts >= 3