Hard
Palindrome Removal — C++
Full explanation · Time O(n^3) · Space O(n^2)
// Time: O(n^3)
// Space: O(n^2)
class Solution {
public:
int minimumMoves(vector<int>& arr) {
vector<vector<int>> dp(arr.size() + 1, vector<int>(arr.size()));
for (int l = 1; l <= arr.size(); ++l) {
for (int i = 0; i + l - 1 < arr.size(); ++i) {
int j = i + l - 1;
if (l == 1) {
dp[i][j] = 1;
} else {
dp[i][j] = 1 + dp[i + 1][j];
if (arr[i] == arr[i + 1]) {
dp[i][j] = min(dp[i][j], 1 + dp[i + 2][j]);
}
for (int k = i + 2; k <= j; ++k) {
if (arr[i] == arr[k]) {
dp[i][j] = min(dp[i][j], dp[i + 1][k - 1] + dp[k + 1][j]);
}
}
}
}
}
return dp[0][arr.size() - 1];
}
};