Easy
Pairs of Songs With Total Durations Divisible by 60 — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int numPairsDivisibleBy60(vector<int>& time) {
int result = 0;
vector<int> counter(60);
for (const auto& t : time) {
result += counter[(60 - t % 60) % 60];
++counter[t % 60];
}
return result;
}
};