Medium
Numbers With Same Consecutive Differences — Python
Full explanation · Time O(2^n) · Space O(2^n)
# Time: O(2^n)
# Space: O(2^n)
class Solution(object):
def numsSameConsecDiff(self, N, K):
"""
:type N: int
:type K: int
:rtype: List[int]
"""
curr = range(10)
for i in xrange(N-1):
curr = [x*10 + y for x in curr for y in set([x%10 + K, x%10 - K])
if x and 0 <= y < 10]
return curr