Hard
Number of Valid Subarrays — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
class Solution {
public:
int validSubarrays(vector<int>& nums) {
int result = 0;
vector<int> s;
for (const auto& num : nums) {
while (!s.empty() && s.back() > num) {
s.pop_back();
}
s.emplace_back(num);
result += s.size();
}
return result;
}
};