Medium
Number of Subarrays With GCD Equal to K — Python
Full explanation · Time O(nlogr) · Space O(logr)
# Time: O(nlogr), r = max(nums)
# Space: O(logr)
# dp
class Solution(object):
def subarrayGCD(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
def gcd(a, b):
while b:
a, b = b, a%b
return a
result = 0
dp = collections.Counter()
for x in nums:
new_dp = collections.Counter()
if x%k == 0:
dp[x] += 1
for g, cnt in dp.iteritems():
new_dp[gcd(g, x)] += cnt
dp = new_dp
result += dp[k]
return result
# Time: O(n^2)
# Space: O(1)
# brute force
class Solution2(object):
def subarrayGCD(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
def gcd(a, b):
while b:
a, b = b, a%b
return a
result = 0
for i in xrange(len(nums)):
g = 0
for j in xrange(i, len(nums)):
if nums[j]%k:
break
g = gcd(g, nums[j])
result += int(g == k)
return result