Hard
Number of Subarrays That Match a Pattern II — C++
Full explanation · Time O(n) · Space O(m)
// Time: O(n)
// Space: O(m)
// kmp
class Solution {
public:
int countMatchingSubarrays(vector<int>& nums, vector<int>& pattern) {
const auto& KMP = [](const auto& text, const auto& pattern) {
const auto& getPrefix = [](const auto& pattern) {
vector<int> prefix(size(pattern), -1);
int j = -1;
for (int i = 1; i < size(pattern); ++i) {
while (j != -1 && pattern[j + 1] != pattern[i]) {
j = prefix[j];
}
if (pattern[j + 1] == pattern[i]) {
++j;
}
prefix[i] = j;
}
return prefix;
};
int result = 0;
const vector<int> prefix = getPrefix(pattern);
int j = -1;
for (int i = 0; i < size(text); ++i) {
while (j > -1 && pattern[j + 1] != text[i]) {
j = prefix[j];
}
if (pattern[j + 1] == text[i]) {
++j;
}
if (j == size(pattern) - 1) {
++result;
j = prefix[j];
}
}
return result;
};
for (int i = 0; i + 1 < size(nums); ++i) {
if (nums[i + 1] > nums[i]) {
nums[i] = 1;
} else if (nums[i + 1] < nums[i]) {
nums[i] = -1;
} else {
nums[i] = 0;
}
}
return KMP(nums, pattern);
}
};