Easy
Number of Students Doing Homework at a Given Time — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int busyStudent(vector<int>& startTime, vector<int>& endTime, int queryTime) {
int result = 0;
for (int i = 0; i < startTime.size(); ++i) {
if (startTime[i] <= queryTime && queryTime <= endTime[i]) {
++result;
}
}
return result;
}
};