Number of Ships in a Rectangle
Time O(log(m * n)) · Space O(log(m * n)) · Official statement on LeetCode
Solutions
// Time: O(s * log(m * n)), s is the max number of ships, which is 10 in this problem
// Space: O(log(m * n))
/**
* // This is Sea's API interface.
* // You should not implement it, or speculate about its implementation
* class Sea {
* public:
* bool hasShips(vector<int> topRight, vector<int> bottomLeft);
* };
*/
class Solution {
public:
int countShips(Sea sea, vector<int> topRight, vector<int> bottomLeft) {
int result = 0;
if (topRight[0] >= bottomLeft[0] &&
topRight[1] >= bottomLeft[1] &&
sea.hasShips(topRight, bottomLeft)) {
if (topRight == bottomLeft) {
return 1;
}
const auto& mid_x = (topRight[0] + bottomLeft[0]) / 2;
const auto& mid_y = (topRight[1] + bottomLeft[1]) / 2;
result += countShips(sea, topRight, {mid_x + 1, mid_y + 1});
result += countShips(sea, {mid_x, topRight[1]}, {bottomLeft[0], mid_y + 1});
result += countShips(sea, {topRight[0], mid_y}, {mid_x + 1, bottomLeft[1]});
result += countShips(sea, {mid_x, mid_y}, bottomLeft);
}
return result;
}
};
Beginner Explanation
What is Number of Ships in a Rectangle?
Number of Ships in a Rectangle (LeetCode #1274) is a Hard problem that primarily trains binary search.
How to think about it
- Restate the goal in your own words before coding.
- Work a tiny example by hand so the invariant becomes obvious.
- Identify the pattern — this problem aligns with binary search.
- Only then translate the idea into code.
Why this problem matters
Hard problems force you to combine patterns and prove complexity carefully — interview gold. Official solution notes mention: Divide and Conquer.
AlgoForge explanations are original teaching notes. Always open the official problem statement on LeetCode for constraints and examples.
Interview Walkthrough
Interview approach for Number of Ships in a Rectangle
Opening (30–60 seconds)
- Clarify inputs/outputs and edge cases (empty input, single element, duplicates, overflow).
- State a brute force so the interviewer knows you can solve it naively.
- Propose the optimal direction tied to binary search.
Core solution narrative
- Define the state you track (pointers, DP cell, set membership, stack top, etc.).
- Explain the transition when you process the next element.
- Call out time (O(log(m * n))) and space (O(log(m * n))) before coding.
- Code cleanly; narrate variable names.
What interviewers listen for
- Correctness on edge cases
- Complexity honesty
- Ability to discuss trade-offs (e.g., hash map space vs. sort + two pointers)
Follow-up questions they may ask
- Can you solve it with less memory?
- What if the input stream is infinite / doesn't fit in RAM?
- How would tests look for adversarial inputs?
Optimized Approach
Optimized solution notes
The reference solutions on AlgoForge target O(log(m * n)) time and O(log(m * n)) space.
Pattern focus: binary search
Use the pattern as a checklist:
- binary search — confirm the invariant holds after each step
Multiple methods appear in the source solutions — compare them and explain when each is preferable.
Implementation tips
- Prefer readable names over micro-optimizations in interviews.
- Extract helpers only when they clarify (e.g., expand-around-center, DFS visit).
- After AC-level logic, re-scan for off-by-one and null checks.
Complexity Analysis
Complexity
| Measure | Bound |
|---|---|
| Time | O(log(m * n)) |
| Space | O(log(m * n)) |
How to justify this in an interview
- Time: count loops, map/set operations, and recursive branching; state average vs worst case if relevant.
- Space: include hash maps, recursion stack, and output allocation when the problem asks for it.
If your implementation differs from the reference, re-derive big-O from your code — never memorize a complexity you cannot defend.
Common Mistakes
Common mistakes on Number of Ships in a Rectangle
- Skipping edge cases — empty collections, single-element inputs, max constraints.
- Wrong invariant for binary search — updating state too early or too late.
- Mutating input unexpectedly when the problem forbids it.
- Off-by-one in windows, ranges, or binary search bounds.
- Ignoring overflow / precision for integer arithmetic problems.
- Overengineering — jumping to an advanced structure when a simpler approach works.
Alternative Approaches
Alternatives
The source file includes more than one method. Compare:
- Primary optimized path — best complexity for typical interviews.
- Secondary approach — often brute force, sorting-based, or space-optimized variant.
Practice articulating when you would pick each (constraints, readability, follow-ups).
Edge Cases
Edge cases checklist
- Minimum input size
- Maximum input size / time limits
- Duplicates and already-sorted input
- Negative numbers / zeros (if applicable)
- Disconnected structures (graphs/trees)
- Single path vs branching recursion depth
Pattern Recognition
Spotting this pattern
Signal phrases that point to binary search:
- Sorted input or ability to sort without changing the answer class
- Need for contiguous subarray / substring → consider sliding window
- Need for O(1) membership → hash set/map
- Optimal substructure + overlapping subproblems → DP
- Connectivity / components → graph DFS/BFS or Union-Find
Primary topics: binary search.
Follow-up Interview Questions
Follow-ups
- How does the solution change if the input is a stream?
- Can you solve it in-place?
- What if duplicates must be handled differently?
- How would you parallelize the approach?
- Design tests that would break a buggy implementation.
Practice Recommendations
What to practice next
- Re-solve Number of Ships in a Rectangle in a second language (cpp, python).
- Drill 3–5 more problems tagged binary search.
- Teach the solution out loud in under 5 minutes.
- Add this problem to your revision calendar in 3 days and 14 days.
Visualization
Study checklist
- Read the official problem statement on LeetCode
- Solve on paper / whiteboard first
- Implement the binary search approach
- Verify edge cases from the checklist
- State time and space complexity aloud
- Compare with the AlgoForge reference solution
- Schedule a revision session
Revision notes
Number of Ships in a Rectangle (#1274) — Hard. Pattern: binary search. Complexity: O(log(m * n)) time / O(log(m * n)) space. Re-derive the invariant before coding.
FAQs
What is the time complexity of Number of Ships in a Rectangle?+
The reference solutions aim for O(log(m * n)) time and O(log(m * n)) space. Always re-derive complexity from the code you write in the interview.
What pattern does Number of Ships in a Rectangle use?+
It primarily maps to binary search, within the broader topic of binary search.
Is Number of Ships in a Rectangle good for interviews?+
Yes — as a Hard problem it is a solid practice target. Pair it with related problems in the same pattern family for spaced repetition.
Where can I read the official statement?+
Open the official LeetCode page for constraints and examples: https://leetcode.com/problems/number-of-ships-in-a-rectangle/